For what values of y is \;y + 2/8y² - 10y + 3 not defined?

Correct Answer is : 34\;3/443, 12\;1/221

Correct Answer is : 34\;3/443, 12\;1/221

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WAEC Mathematics 2024 Paper

Question : 50

Total: 50

\;\frac{y + 2}{8y^2 - 10y + 3}

not defined?

Solution:

Concept:

A fraction is not defined when its denominator equals zero.

Explanation:

Set the denominator equal to zero:

8y^2 - 10y + 3 = 0

Factorize the quadratic:

8y^2 - 6y - 4y + 3 = 0

2y(4y - 3) - 1(4y - 3) = 0

(4y - 3)(2y - 1) = 0

So,

4y - 3 = 0

2y - 1 = 0

This gives

y = \frac{3}{4}

y = \frac{1}{2}

Answer:

The expression is not defined for

y = \frac{3}{4}

and

y = \frac{1}{2}

. Option C.

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