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WAEC Mathematics 2020 Paper

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Question : 35

Total: 48

The diameter of a sphere is 12 cm. Calculate, correct of the nearest cm

^{3}

, the volume of the sphere, [Take

\pi = \frac{22}{7}

]

903 cm $^{3}$
904 cm $^{3}$
905 cm $^{3}$
906 cm $^{3}$

Solution:

Concept:

The volume of a sphere is calculated using the formula

V = \frac{4}{3}\pi r^3

.

Explanation:

The diameter of the sphere is

d = 12\text{ cm}

.

So, the radius is

r = \frac{d}{2} = \frac{12}{2} = 6\text{ cm}

.

Substitute

r = 6

and

\pi = \frac{22}{7}

into the volume formula.

V = \frac{4}{3} \times \frac{22}{7} \times 6^3

V = \frac{4}{3} \times \frac{22}{7} \times 216

V = \frac{6336}{7} = 905.14\ldots

Correct to the nearest cubic centimetre,

V \approx 905\text{ cm}^3

.

Answer:

905\text{ cm}^3

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