Africa Exams
Where Preparation Meets Success
Home
Botswana
Botswana PSLE Papers
Botswana JCE Papers
Botswana BGCSE Papers
Ghana
Ghana BECE Exams
Kenya
Kenya KCPE Papers
Kenya KCSE Papers
Kenya KASNEB Papers
Nigeria
WAEC Exams
JAMB Exams
Rwanda
Rwanda Primary Papers
Rwanda Secondary Papers
Uganda
Uganda PLE Papers
Uganda UCE Papers
Uganda UACE Papers
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Contact Us
Our Apps
Privacy
+
-
Test Index
WAEC Mathematics 2020 Paper
Show Para
Hide Para
Share question:
© africaexams.com
Question : 34
Total: 48
Find the sum of the interior angle of a pentagon.
340
o
^o
o
350
o
^o
o
540
o
^o
o
550
o
^o
o
Validate
Solution:
Concept:
For any polygon with
n
n
n
sides, the sum of interior angles is
(
n
−
2
)
×
18
0
∘
(n - 2) \times 180^\circ
(
n
−
2
)
×
18
0
∘
.
Explanation:
A pentagon has
5
5
5
sides, so
n
=
5
n = 5
n
=
5
.
Substitute
n
=
5
n = 5
n
=
5
into the formula:
Sum
=
(
5
−
2
)
×
18
0
∘
= (5 - 2) \times 180^\circ
=
(
5
−
2
)
×
18
0
∘
Sum
=
3
×
18
0
∘
= 3 \times 180^\circ
=
3
×
18
0
∘
Sum
=
54
0
∘
= 540^\circ
=
54
0
∘
Answer:
54
0
∘
540^\circ
54
0
∘
, which is option C.
© africaexams.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
Prev Question
Next Question