WAEC Mathematics 2018 Paper

Concept:To find the points where two graphs meet, equate their $y$-expressions and solve for $x$.Explanation:The two curves are $y = x^2$ and $y = x$.At their intersection, the $y$-values are identical, so we equate the right-hand sides.This gives $x^2 = x$.Bring all terms to one side: $x^2 - x = 0$.Factorize the quadratic: $x(x-1) = 0$.Using the zero product rule, $x = 0$ or $x = 1$.Now find the corresponding $y$-values.For $x = 0$, substitute into $y = x$: $y = 0$.For $x = 1$, substitute into $y = x$: $y = 1$.Thus the intersection points are $(0,0)$ and $(1,1)$.These satisfy both original equations, confirming they are the only solutions.Answer:Option A: $(0,0)$ and $(1,1)$.