Concept:For a quadratic equation y=ax2+bx+c with a>0, the minimum value occurs at x=−2ab.Explanation:The given relation is y=2x2+x−1.Here, a=2 and b=1.At the minimum point, x=−2ab=−2(2)1=−41=−0.25.Substitute x=−0.25 into the equation to find the minimum value of y:y=2(−0.25)2+(−0.25)−1y=2(0.0625)−0.25−1y=0.125−0.25−1=−1.125On the graph, this value is read as approximately −1.25.Among the given options, −1.25 is the best match.Answer:C. −1.25
