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JAMB Physics 2024 Paper

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Question : 78

Total: 125

Calculate the power of an object which moves through a distance of 500cm in 1s on a frictionless surface by a horizontal force of 50N

200W
300W
350W
250W

Solution:

Power = $\; \frac{w}{t}$

Given: F = 50N, s = 500cm → 5m and t = 1s

W = f x s = 250 x 5 = 250J

Power = $\; \frac{250}{1}$ = 250W

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