Electric field intensity (E) = forcecharge\frac{\text{force}}{\text{charge}}chargeforce = Fq\frac{\text{F}}{\text{q}}qF
Given: E = 1200Vm−1^{-1}−1, q = 1.6 x 10 −19^{-19}−19C, m = 9.1 x 10−31^{-31}−31kg
F = E x q
F = 1.6 x 10−19^{-19}−19 x 1200 = 1.92 x 10−16^{-16}−16N
F = ma
a = Fm\frac{F}{m}mF = 1.92×10−169.1×10−31\frac{1.92\times 10^{-16}}{9.1\times 10^{-31}}9.1×10−311.92×10−16 ≈eq\approx eq≈eq 2.11 x 1014^{14}14ms−2^{-2}−2
