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JAMB Physics 2023 Paper

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Question : 4

Total: 65

A missile is launched with a speed of 75 ms-1 at an angle of 22° above the surface of a warship. Find the horizontal range achieved by the missile. Ignore the effects of air resistance.

[Take g = 10 ms-2]

195
271 m
391 m
136 m

Solution:

U= 75 $\mathrm{ms}^{-1}$ =22º, g= 10 $\mathrm{ms}^{-2}$ , R=?

R= $\frac{U^2 \sin 2\theta}{g}$

⇒R=

\frac{75^2 \times \sin 2(22)}{10}

⇒R=

\frac{5625 \times \sin 44}{10}

⇒R= $\frac{5625 \times 0.6947}{10}$

⇒R=

\frac{3907.69}{10}

⇒ 391m

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