Find the tension in the two cords shown in the figure above. Neglect the mass of the cords, and assume that the angle is 38° and the mass m is 220 kg
[Take g = 9.8 ms-2]
W = mg = 220 x 9.8 = 2156 N
⇒ T1T_1T1 = 2156sin38\frac{2156}{\sin 38}sin382156
⇒ T1T_1T1 = 3502 N
Cos 38º = T2T1\frac{T_2}{T_1}T1T2
⇒ T2T_2T2 = 3502 x Cos 38º
⇒ T2T_2T2 = 2760 N
; T1T_1T1 = 3502 N, T2T_2T2 = 2760 N.
