JAMB Physics 2023 Paper

Concept:The mass is in equilibrium, so the sum of vertical and horizontal forces must each be zero. The weight is balanced by the vertical component of the slanting cord, while the horizontal cord balances the horizontal component.Explanation:First, find the weight of the mass:$$W = mg = 220 \times 9.8 = 2156\ \text{N}$$The vertical component of $T_1$ supports the weight, so:$$T_1 \sin 38^\circ = W$$Solving for $T_1$:$$T_1 = \frac{2156}{\sin 38^\circ} \approx 3502\ \text{N}$$For horizontal equilibrium, $T_2$ equals the horizontal component of $T_1$:$$T_2 = T_1 \cos 38^\circ$$Substitute the value of $T_1$:$$T_2 = 3502 \times \cos 38^\circ \approx 2760\ \text{N}$$Answer:$$T_1 = 3502\ \text{N}, \quad T_2 = 2760\ \text{N}$$This matches option C.