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JAMB Physics 2022 Paper

Question : 35

Total: 40

^{-1}

in 20 seconds. The power developed in the engine is?

Solution:

where force = f, mass = m, acceleration = a, velocity = v, time = t

Force = m * a → m * $\frac{\Delta v}{t}$

Power = f * v

P = m * $\frac{v}{t}$ * v = m * $\frac{v^2}{t}$

p = $\frac{1600 \cdot 25^2}{20}$

p = 50,000 or 50 KW

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