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JAMB Physics 2022 Paper

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Question : 34

Total: 40

What quantity of heat is required to convert 20 g of ice at 0 ºC to water at the same temperature? (Specific latent heat of ice = 336 Jg

^{-1}

)

7.06 x 10 $^{3}$ J
5.38 x 10 $^{3}$ J
6.72 x 10 $^{3}$ J
1.35 x 10 $^{3}$ J

Solution:

Concept:

Heat needed to change ice to water at constant temperature depends on mass and specific latent heat of fusion.

Explanation:

The formula for heat absorbed during a phase change is:

Q = m \times L

Where:

m = 20 \, \text{g}

is the mass of ice,

L = 336 \, \text{Jg}^{-1}

is the specific latent heat of ice.

Substitute the values:

Q = 20 \times 336

Q = 6720 \, \text{J}

Expressing in standard form:

Q = 6.72 \times 10^{3} \, \text{J}

Answer:

6.72 \times 10^{3} \, \text{J}

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