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JAMB Physics 2022 Paper

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Question : 34

Total: 40

What quantity of heat is required to convert 20 g of ice at 0 ºC to water at the same temperature? (Specific latent heat of ice = 336 Jg

^{-1}

)

7.06 x 10 $^{3}$ J
5.38 x 10 $^{3}$ J
6.72 x 10 $^{3}$ J
1.35 x 10 $^{3}$ J

Solution:

quantity of heat = mass * Specific latent heat → 20 * 336

quantity of heat = 6720j or 6.72 x 10 $^{3}$ J

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