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JAMB Mathematics 2022 Paper

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Question : 30

Total: 39

Given that S =

3t^{2}

+ 5t - 10 is displacement of a particle in metres, calculate it initial velocity.

10m/s
2m/s
5m/s
6m/s

Solution:

Concept:

Initial velocity is the rate of change of displacement at time

t = 0

.

Explanation:

Differentiate displacement

S

with respect to time

t

to get velocity

v

.

S = 3t^{2} + 5t - 10

v = \frac{dS}{dt} = 6t + 5

At the initial time,

t = 0

.

v(0) = 6(0) + 5 = 5

Thus, the initial velocity is

5 \ \text{m/s}

.

Answer:

C.

5 \ \text{m/s}

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