JAMB Mathematics 2018 Paper

Concept:Probability of consecutive independent draws with replacement requires multiplying the individual probabilities.Explanation:Total balls in the box: $2 + 4 = 6$.Probability of drawing a red ball on the first draw:$P(\text{red}) = \frac{2}{6} = \frac{1}{3}$.Since the ball is replaced, the box contents do not change.So the probability of drawing a red ball on the second draw is also $\frac{1}{3}$.Therefore, the probability of drawing two red balls is:$P(\text{red and red}) = \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}$.Answer:$\frac{1}{9}$ (Option D).