Concept:In a DC circuit, a capacitor charges quickly and then blocks the flow of current.
Explanation:When the switch is closed, the capacitor is uncharged and behaves like a short circuit.
So current flows through the circuit and the LED lights up briefly.
As the capacitor charges, its voltage increases and it opposes the current.
Within a short time, the capacitor becomes fully charged and acts like an open circuit.
Then no current flows through the circuit, so the LED stops glowing.
Therefore, the LED flashes for a moment and then goes off.
Answer:B. flashes and goes off.