specific heat capacity of water = 4200Jkg−1k−1, Specific heat of vaporization of water = 2.26 x 106Jkg−1, mass of water = 0.02kg, water vapour temp. = 100ºC, water at 97ºC
The amount of heat required = ML + McΔθ
= 0.02 x 2.26 x 106 + 0.02 x 4200 x (100 - 97)
= 45,200 + 252 = 45,452J.