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WAEC Physics 2024 Paper

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Question : 20

Total: 50

A particle of mass 3.6 x 10

^{-6}

kg revolving around the earth has a radial acceleration of 4.3 x 10

^7

^{-2}

. Calculate the centripetal force of the particle.

1.55 x 10 $^2$ N
2.00 x 10 $^{-2}$ N
6.25 x 10 $^{-14}$ N
1.00 x 10 $^2$ N

Solution:

F = mass x acceleration due to gravity

F $_c$ = m x a $_c$

a $_c$ = a $_r$ = 4.3 x 10 $^7$ ms $^{-2}$ , m = 3.6 x 10 $^{-6}$ kg

F $_c$ = m x a $_c$ = 3.6 x 10 $^{-6}$ x 4.3 x 10 $^7$ = 154.8N ≈ 155N ⇒ 1.55 x 10 $^2$ N

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