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WAEC Physics 2023 Paper

Question : 45

Total: 50

Solution:

Concept:

For an object starting from rest, distance is proportional to acceleration when time is fixed.

Explanation:

Let acceleration of A be

a

Acceleration of B is twice that of A, so it is

2a

Both start from rest, meaning initial velocity

u = 0

Using

s = ut + \frac{1}{2} a t^2

for the same time

t

s_A = \frac{1}{2} a t^2

s_B = \frac{1}{2} (2a) t^2 = a t^2

Thus,

s_B = 2s_A

Answer:

B travels two times as far as A.

So the correct option is C.

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