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WAEC Physics 2022 Paper

Question : 3

Total: 50

Solution:

Concept:

The time period of a simple pendulum is proportional to the square root of its length:

T = 2\pi\sqrt{\frac{L}{g}}

Explanation:

Let the original length be

L

and the original period be

T

The new length is

L' = 4L

The new period is:

T' = 2\pi\sqrt{\frac{L'}{g}} = 2\pi\sqrt{\frac{4L}{g}} = 2\left(2\pi\sqrt{\frac{L}{g}}\right) = 2T.

Therefore, when the length becomes four times, the period becomes twice the original period.

Answer:

The period increases by a factor of

2

Correct option: B. $2$

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