Africa Exams
Where Preparation Meets Success
Home
Botswana
Botswana PSLE Papers
Botswana JCE Papers
Botswana BGCSE Papers
Ghana
Ghana BECE Exams
Kenya
Kenya KCPE Papers
Kenya KCSE Papers
Kenya KASNEB Papers
Nigeria
WAEC Exams
JAMB Exams
Rwanda
Rwanda Primary Papers
Rwanda Secondary Papers
Uganda
Uganda PLE Papers
Uganda UCE Papers
Uganda UACE Papers
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Contact Us
Our Apps
Privacy
+
-
Test Index
WAEC Physics 2020 Paper
Show Para
Hide Para
Share question:
© africaexams.com
Question : 36
Total: 51
In an electric circuit, an inductor of inductance 0.5 H and resistance
50
Ω
is connected to an alternating current source of frequency 60 Hz . Calculate the impedance of the circuit.
50.0
Ω
450.5
Ω
195.0
Ω
1950.1
Ω
Validate
Solution:
The impedance of a R-L circuit is given by:
Z
=
√
(
R
2
+
X
L
2
)
⋯
−
⋯
−
⋯
where
Z
is the impedance,
R
is the resistance, and
XL is the inductive reactance
where
f
is the frequency
From eqn(2),
X
L
=
2
*
π
*
60
*
0.5
=
60
π
Also, from eqn(1),
Z
=
√
(
50
2
+
(
60
π
)
2
)
Z
=
195.0
Ω
© africaexams.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
Prev Question
Next Question