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WAEC Physics 2018 Paper

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Question : 50

Total: 50

A nuclide is represented by

{}_{32}^{70}\mathrm{B}

. Determine its neutron-proton ratio

0.5
0.8
1.2
1.5

Solution:

Concept:

The neutron-proton ratio is the number of neutrons divided by the number of protons in the nucleus.

Explanation:

For the nuclide

{}_{32}^{70}\mathrm{B}

:

Mass number

A = 70

Atomic number

Z = 32

Number of protons

= Z = 32

Number of neutrons

= A - Z = 70 - 32 = 38

Neutron-proton ratio

= \frac{38}{32} = 1.1875

This rounds to

1.2

.

Answer:

C.

1.2

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