Africa Exams
Where Preparation Meets Success
Home
Botswana
Botswana PSLE Papers
Botswana JCE Papers
Botswana BGCSE Papers
Ghana
Ghana BECE Exams
Kenya
Kenya KCPE Papers
Kenya KCSE Papers
Kenya KASNEB Papers
Nigeria
WAEC Exams
JAMB Exams
Rwanda
Rwanda Primary Papers
Rwanda Secondary Papers
Uganda
Uganda PLE Papers
Uganda UCE Papers
Uganda UACE Papers
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Contact Us
Our Apps
Privacy
+
-
Test Index
WAEC Physics 2017 Paper
Show Para
Hide Para
Share question:
© africaexams.com
Question : 7
Total: 50
A body weighing 14N in air is partially immersed in water. If the mass of water displaced in the process is 200g, calculate the upthrust on the body. [g=10
m/s
2
\text{m/s}^2
m/s
2
]
2.0N
3.0N
3.5N
7.0N
Validate
Solution:
Concept:
Archimedes’ principle states that the upthrust equals the weight of the fluid displaced.
Explanation:
Mass of water displaced
=
200
g
=
0.2
kg
= 200\text{ g} = 0.2\text{ kg}
=
200
g
=
0.2
kg
.
Upthrust
=
=
=
weight of displaced water
=
mass
×
g
= \text{mass} \times g
=
mass
×
g
.
So, upthrust
=
0.2
×
10
=
2.0
N
= 0.2 \times 10 = 2.0\text{ N}
=
0.2
×
10
=
2.0
N
.
Answer:
A.
2.0
N
2.0\text{ N}
2.0
N
© africaexams.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
Prev Question
Next Question