Test Index

WAEC Physics 2015 Paper

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Question : 28

Total: 50

A swimming pool is 2.1m deep. If it contains water of refractive index 1.3, calculate the apparent depth of pool

3.4m
2.7m
1.6m
0.8m

Solution:

Concept:

Refractive index relates real depth and apparent depth as

\mu = \frac{\text{real depth}}{\text{apparent depth}}

.

Explanation:

Given real depth

= 2.1\,\text{m}

and refractive index

\mu = 1.3

.

Using

\mu = \frac{\text{real depth}}{\text{apparent depth}}

:

1.3 = \frac{2.1}{\text{apparent depth}}

\text{apparent depth} = \frac{2.1}{1.3} = 1.615\,\text{m}

Rounding off gives

1.6\,\text{m}

.

Answer:

C.

1.6\,\text{m}

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