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WAEC Physics 2014 Paper

Question : 39

Total: 48

A 15

\mu\mathrm{F}

\pi = 3.142

]

Solution:

Concept:

Capacitive reactance measures how a capacitor resists alternating current.

Explanation:

The formula for capacitive reactance is

X_C = \frac{1}{2\pi f C}

Here,

f = 50\,\mathrm{Hz}

C = 15\,\mu\mathrm{F} = 15 \times 10^{-6}\,\mathrm{F}

, and

\pi = 3.142

Substitute these values into the formula:

X_C = \frac{1}{2 \times 3.142 \times 50 \times 15 \times 10^{-6}}

First, calculate the denominator:

2 \times 3.142 \times 50 \times 15 \times 10^{-6} = 0.004713

Then,

X_C = \frac{1}{0.004713} \approx 212.18\,\Omega

This is closest to the option 212

\Omega

Answer:

D. 212

\Omega

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