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WAEC Physics 2013 Paper

Question : 8

Total: 46

^{-2}

]. Calculate the speed of projection

Solution:

Concept:

For vertical projection, the time to reach maximum height is half the total time of flight. At maximum height, final velocity is zero.

Explanation:

Total time of flight is

1.2\,\mathrm{s}

Time to reach maximum height,

t = \frac{1.2}{2} = 0.6\,\mathrm{s}

At maximum height,

v = 0

Using

v = u - gt

, we get

0 = u - 10 \times 0.6

Therefore,

u = 10 \times 0.6 = 6.0\,\mathrm{ms}^{-1}

Answer:

The speed of projection is

6.0\,\mathrm{ms}^{-1}

, which is option B.

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