Test Index

WAEC Physics 2013 Paper

Question : 42

Total: 46

Solution:

Concept:

Use Newton's second law of motion: the net force on the block equals its mass multiplied by its acceleration.

Explanation:

The applied pulling force is

P = 40\,\text{N}

The frictional force is

F = 12\,\text{N}

Net force acting on the block is

P - F = 40 - 12 = 28\,\text{N}

Mass of the block is

m = 5\,\text{kg}

Using

a = \frac{\text{Net force}}{m}

, we get:

a = \frac{28}{5} = 5.6\,\text{m/s}^2

Answer:

The magnitude of the acceleration of the block is

5.6\,\text{m/s}^2

Correct option: B.

Go to Question:

Prev Question

Next Question