WAEC Physics 2013 Paper

Concept:Heat generated in a resistor is the electrical energy converted into thermal energy, given by the formula $Q = \frac{V^2 t}{R}$.Explanation:The time must be converted into seconds because the standard unit of time in these calculations is the second.Therefore, $t = 10 \times 60 = 600 \, \text{s}$.Since the potential difference across the resistor is constant, use the formula:$$Q = \frac{V^2 t}{R}$$Substitute the given values: $V = 12 \, \text{V}$, $R = 6 \, \Omega$, and $t = 600 \, \text{s}$.$$Q = \frac{12^2 \times 600}{6}$$Simplify the expression:$$Q = \frac{144 \times 600}{6}$$$$Q = \frac{86400}{6} = 14400 \, \text{J}$$Answer:The quantity of heat generated is $14400 \, \text{J}$, so the correct option is C.