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WAEC Mathematics 2024 Paper

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Question : 46

Total: 50

The probability that Amaka will pass an examination is

\frac{3}{7}

and that Bala will pass is

\frac{4}{9}

. Find the probability that both will pass the examination.

$\frac{2}{21}$
$\frac{4}{21}$ .
$\frac{5}{21}$
$\frac{9}{21}$

Solution:

Concept:

For independent events, the probability that both events occur is the product of their individual probabilities.

Explanation:

Probability that Amaka passes

= \frac{3}{7}

.

Probability that Bala passes

= \frac{4}{9}

.

Both are independent events.

So, probability both pass

= \frac{3}{7} \times \frac{4}{9}

.

Simplify:

\frac{3 \times 4}{7 \times 9} = \frac{12}{63}

.

Reduce:

\frac{12}{63} = \frac{4}{21}

.

Answer:

\frac{4}{21}

, which is option B.

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