Concept:Use bearing angles to find the north-south component of the distance between P and Q.Explanation:The bearing of P from Q is 330∘, so P is 30∘ west of north from Q.Therefore, Q is 30∘ east of south from P.Let d be the required distance that Q is south of P.Using the right triangle formed with the north-south line:d=25cos30∘Since cos30∘=sin60∘, we can also write:d=25sin60∘d=25×0.8660d=21.65mSo d≈21.7m.
