In the diagram above, MN||KL, ML and KN intersect at X. |MN| = 12cm, |MX| = 10cm and |MN| = 9cm. If the area of △ MXN is 16cm2, calculate the area of △ LXK
MN||KL, △ LXK is similar to △MXN
So, the ratio of the areas of the two similar triangles equals the square of the ratio of their corresponding sides
Therefore, Areaof△MXNAreaof△LXK=12292
16Areaof△LXK=14481
Area of △LXK = 16×81144=9cm2
