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WAEC Mathematics 2024 Paper

Question : 14

Total: 50

\; \frac{22}{7}

)

Solution:

Concept:

Total surface area of a cylinder closed at one end is the sum of the area of one circular base and the curved surface area.

Explanation:

The required surface area is given by:

A = \pi r^2 + 2\pi rh = \pi r(r + 2h)

Here,

r = 0.245\,\text{m}

and

h = 2.5\,\text{m}

Substitute the values:

A = \frac{22}{7} \times 0.245 \times (0.245 + 2 \times 2.5)

A = \frac{22}{7} \times 0.245 \times (0.245 + 5)

A = 0.77 \times 5.245

A = 4.03865\,\text{m}^2

Correct to one decimal place:

A \approx 4.0\,\text{m}^2

Answer:

The total surface area of the barrel is

4.0\,\text{m}^2

, which is Option C.

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