Concept:Forming and solving linear equations from given conditions.Explanation:Let the two numbers be x and y.One-third of their sum is 12:31(x+y)=12x+y=36...(i)Twice their difference is 12:2(x−y)=12x−y=6...(ii)Add equations (i) and (ii):(x+y)+(x−y)=36+62x=42x=21Substitute x=21 into equation (i):21+y=36y=15Thus, the two numbers are 21 and 15, which matches option C.Answer:The numbers are 21 and 15.Correct option: C. 21 and 15.