make x the subject of the relation y = ax³ - b/3z

Correct Answer is : x = 3yz+ba3[3]{3yz + b/a}3a3yz+b

Correct Answer is : x = 3yz+ba3[3]{3yz + b/a}3a3yz+b

Test Index

WAEC Mathematics 2023 Paper

Question : 22

Total: 50

y = \frac{ax^3 - b}{3z}

Solution:

Concept:

Make

x

the subject by isolating

x^3

and applying the cube root.

Explanation:

Given

y = \frac{ax^3 - b}{3z}

Cross multiply:

3yz = ax^3 - b

Add

b

to both sides:

3yz + b = ax^3

Divide both sides by

a

x^3 = \frac{3yz + b}{a}

Take the cube root of both sides:

x = \sqrt[3]{\frac{3yz + b}{a}}

Answer:

x = \sqrt[3]{\frac{3yz + b}{a}}

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