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WAEC Mathematics 2023 Paper

Question : 2

Total: 50

Solve

1 + \sqrt[3]{x - 3} = 4

Solution:

Concept:

Isolate the cube root term first, then cube both sides to remove the radical and solve for

x

Explanation:

Start with the given equation:

1 + \sqrt[3]{x - 3} = 4

Subtract

1

from both sides to isolate the cube root:

\sqrt[3]{x - 3} = 4 - 1

\sqrt[3]{x - 3} = 3

Cube both sides to eliminate the cube root:

(\sqrt[3]{x - 3})^3 = 3^3

x - 3 = 27

Add

3

to both sides:

x = 27 + 3

x = 30

Check the solution:

1 + \sqrt[3]{30 - 3} = 1 + \sqrt[3]{27} = 1 + 3 = 4

This matches the original equation.

Answer:

x = 30

, so the correct option is A.

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