∠SOR = 2 × 28° = 56° (angle at the centre is twice the angle at the circumference)
∠ORS = 180∘ − 56∘2=124∘2\; \frac{180^{\circ} \; - \; 56^{\circ}}{2} = \frac{124^{\circ}}{2}2180∘−56∘=2124∘ ( base angles of isosceles triangle are equal)
∴ ∠ORS = 62°
