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WAEC Mathematics 2022 Paper

Question : 6

Total: 47

If 4

^{3x}

^{x+1}

, find the value of x

Solution:

Concept:

Rewrite both sides of the exponential equation with the same base, then equate the exponents.

Explanation:

Given:

4^{3x} = 16^{x+1}

Write

16

4^2

, so the equation becomes:

4^{3x} = (4^2)^{x+1}

4^{3x} = 4^{2(x+1)}

Since the bases are equal, equate the exponents:

3x = 2(x+1)

3x = 2x + 2

3x - 2x = 2

x = 2

Answer:

x = 2

, which corresponds to option A.

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