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WAEC Mathematics 2022 Paper

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Question : 46

Total: 47

Given that log

_3

27 = 2x + 1, find the value of x.

0
1
2
3

Solution:

Concept:

Evaluate the logarithm using the fact that

27 = 3^3

, then solve the resulting linear equation.

Explanation:

Since

27 = 3^3

, we can write:

\log_3 27 = \log_3 3^3

Using the power rule of logarithms:

= 3 \cdot \log_3 3 = 3 \cdot 1 = 3

So the given equation becomes:

3 = 2x + 1

Subtract

1

from both sides:

3 - 1 = 2x \implies 2 = 2x

Divide both sides by

2

:

x = 1

Answer:

x = 1

, which corresponds to option B.

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