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WAEC Mathematics 2022 Paper

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Question : 32

Total: 47

Simplify

\;\frac{2-18m^2}{1+3m}

2[1+3m]
2[1-3m]
2[1-3m $^2$ ]
2[1+3m $^2$ ]

Solution:

Concept:

Factorise the numerator as a difference of squares, then cancel the common factor.

Explanation:

Start with

\frac{2-18m^2}{1+3m}

.

Take out the common factor

2

from the numerator:

\frac{2(1-9m^2)}{1+3m}

Write

1-9m^2

as

(1)^2 - (3m)^2

:

\frac{2(1-3m)(1+3m)}{1+3m}

Cancel the common factor

(1+3m)

from numerator and denominator:

2(1-3m)

Answer:

Option B.

2[1-3m]

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