Make t the subject of k = m {t-p/r}

Correct Answer is : k2r+pm2m2{k²r + p m²}{m²}m2k2r+pm2

Correct Answer is : k2r+pm2m2{k²r + p m²}{m²}m2k2r+pm2

Test Index

WAEC Mathematics 2022 Paper

Question : 18

Total: 47

m \sqrt{\frac{t-p}{r}}

Solution:

Concept:

Rearrange the formula by removing the square root and isolating

t

Explanation:

Start with

k = m\sqrt{\frac{t-p}{r}}

Square both sides to remove the square root:

k^2 = m^2 \cdot \frac{t-p}{r}

Multiply both sides by

r

k^2 r = m^2(t-p)

Divide both sides by

m^2

\frac{k^2 r}{m^2} = t - p

Add

p

to both sides:

t = \frac{k^2 r}{m^2} + p

Write

p

with denominator

m^2

t = \frac{k^2 r + p m^2}{m^2}

This matches option B.

Answer:

t = \frac{k^2 r + p m^2}{m^2}

Correct option: B.

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