make u the subject in x =2u-3/3u+2

Correct Answer is : u = 2x+32−3x2x+3/2-3x2−3x2x+3

Correct Answer is : u = 2x+32−3x2x+3/2-3x2−3x2x+3

Test Index

WAEC Mathematics 2021 Paper

Question : 16

Total: 49

\frac{2u-3}{3u+2}

Solution:

Concept:

Rearrange the equation by cross-multiplying, then isolate

u

by collecting and factoring the terms containing

u

Explanation:

Start with

x = \frac{2u-3}{3u+2}

Cross-multiply:

x(3u+2) = 2u-3

Expand the left side:

3ux + 2x = 2u - 3

Collect

u

terms on one side:

2x + 3 = 2u - 3ux

Factor out

u

2x + 3 = u(2 - 3x)

Divide both sides by

(2 - 3x)

u = \frac{2x+3}{2-3x}

Answer:

u = \frac{2x+3}{2-3x}

(Option C).

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