Concept:Equal radii form an isosceles triangle, and an exterior angle of a triangle equals the sum of the two opposite interior angles.Explanation:Since O is the centre of the circle, OP=OQ because both are radii.So △OPQ is isosceles.Therefore, its base angles are equal:∠OQP=∠OPQ=48∘The marked angle M is the exterior angle of △OPQ.Using the exterior angle theorem:M=48∘+48∘=96∘Answer:96∘⇒ Option A.