Make m the subject of the relation k = {m-y/m+1}

Correct Answer is : m = y+k21−k2\;y+k²/1-k²1−k2y+k2

Correct Answer is : m = y+k21−k2\;y+k²/1-k²1−k2y+k2

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WAEC Mathematics 2020 Paper

Question : 13

Total: 48

\sqrt{\frac{m-y}{m+1}}

Solution:

Concept:

Rearranging an equation involving a square root by squaring both sides.

Explanation:

Start with

k = \sqrt{\frac{m-y}{m+1}}

Square both sides to remove the square root:

k^2 = \frac{m-y}{m+1}

Multiply both sides by

m+1

k^2(m+1) = m - y

Expand the left side:

k^2 m + k^2 = m - y

Collect terms containing

m

on one side:

k^2 + y = m - k^2 m

Factor out

m

on the right:

k^2 + y = m(1 - k^2)

Divide both sides by

1 - k^2

m = \frac{y+k^2}{1-k^2}

Answer:

m = \frac{y+k^2}{1-k^2}

, which is option B.

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