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WAEC Mathematics 2019 Paper

Question : 7

Total: 50

Evaluate;

\frac{\log_3 9 - \log_2 8}{\log_3 9}

Solution:

Concept:

Use the logarithm power rule to simplify each log term before subtracting.

Explanation:

Write each argument as a power of its base.

\log_3 9 = \log_3 3^2 = 2

\log_2 8 = \log_2 2^3 = 3

Substitute these values into the given expression.

\frac{\log_3 9 - \log_2 8}{\log_3 9} = \frac{2 - 3}{2}

Simplify the numerator.

= \frac{-1}{2}

Answer:

\frac{-1}{2}

, which is option D.

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