y+12−2y−13\frac{y+1}{2} - \frac{2y-1}{3}2y+1−32y−1 = 41\frac{4}{1}14
- 3(y+1)−2(2y−1)6=41\frac{3(y+1)-2(2y-1)}{6} = \frac{4}{1}63(y+1)−2(2y−1)=14
3y + 3 - 4y + 2 = 24
- y + 5 = 24
- y = 24 - 5 = 19
y = - 19
