Make b the subject of the relation lb = 1/2 (a + b)h

Correct Answer is : ah2l−hah/2l - h2l−hah

Correct Answer is : ah2l−hah/2l - h2l−hah

Test Index

WAEC Mathematics 2019 Paper

Question : 26

Total: 50

\frac{1}{2}

(a + b)h

Solution:

Concept:

Rearrange the equation so that

b

is isolated on one side of the equals sign.

Explanation:

Start with the given equation:

lb = \frac{1}{2}(a + b)h

Multiply both sides by 2 to eliminate the fraction:

2lb = (a + b)h

Expand the right-hand side:

2lb = ah + bh

Subtract

bh

from both sides to group the

b

terms:

2lb - bh = ah

Factor

b

out of the left-hand side:

b(2l - h) = ah

Divide both sides by

2l - h

to make

b

the subject:

b = \frac{ah}{2l - h}

Answer:

b = \frac{ah}{2l - h}

This is option A.

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