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WAEC Mathematics 2018 Paper

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Question : 4

Total: 50

Find the value of x for which

32_{\text{four}} = 22_x

three
five
six
seven

Solution:

$32_4 = 22_x$

$3 \times 4^1 + 2 \times 4^o$ = $2 \times x^1 + 2 \times x^o$

12 + 2 x 1 = 2x + 2 x 1

14 = 2x + 2

14 - 2 = 2x

12 = 2x

x = $\;\frac{12}{2}$

x = 6

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