Test Index

WAEC Mathematics 2018 Paper

Question : 2

Total: 50

Evaluate:

\left(64^{\frac{1}{2}} + 125^{\frac{1}{3}}\right)^2

Solution:

$\left[64^{\frac{1}{2}} + 125^{\frac{1}{3}}\right]^2$ = $\left[ \sqrt{64} + \sqrt[3]{125} \right]^2$

$\left[8+5\right]^2$ = $\left[13\right]^2$

= 169

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