Test Index

WAEC Mathematics 2017 Paper

Question : 41

Total: 49

Marks	0	1	2	3	4	5
Frequency	7	4	18	12	8	11

Solution:

Concept:

Median = value of the

\frac{n}{2}

th item in a frequency distribution.

Explanation:

Total frequency:

n = 7 + 4 + 18 + 12 + 8 + 11 = 60

Median position:

\frac{n}{2} = \frac{60}{2} = 30

th item.

Cumulative frequencies: 7, 11, 29, 41, 49, 60.

The 30th item lies in the class with mark 3 because the cumulative frequency reaches 41 at mark 3.

Hence, the median mark is 3.

Answer:

Median = 3 (Option B).

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