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WAEC Mathematics 2017 Paper

Question : 39

Total: 49

^o

Solution:

Concept:

Use the angle in a semicircle and the exterior angle property of a triangle.

Explanation:

Since

ZY

is a diameter of the circle,

\angle ZWY = 90^\circ

(angle subtended in a semicircle).

\triangle ZYW

\angle ZYW = 33^\circ

Therefore,

\angle WZY = 180^\circ - (90^\circ + 33^\circ) = 57^\circ

From the diagram,

X

lies on the extension of

YW

\angle ZWX

is the exterior angle of

\triangle ZYW

W

Thus,

\angle ZWX = 57^\circ + 33^\circ = 90^\circ

Answer:

\angle ZWX = 90^\circ

(Option C).

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