x∝1yx \propto \frac{1}{y}x∝y1, y ∝\propto∝ z
x = ky\frac{k}{y}yk
y = mz
Since y = mz,
x = kmz\frac{k}{mz}mzk, where k and m are constants. Hence,
x ∝\propto∝ 1z\frac{1}{z}z1