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WAEC Mathematics 2016 Paper

Question : 42

Total: 49

The relation y = x² + 2x + k passes through the point (2,0). Find the value of k

Solution:

Concept:

If a point lies on a curve, its coordinates must satisfy the equation of the curve.

Explanation:

The given equation is

y = x^2 + 2x + k

The point is

(2,0)

, so substitute

x = 2

and

y = 0

0 = (2)^2 + 2(2) + k

0 = 4 + 4 + k

0 = 8 + k

Therefore,

k = -8

Answer:

k = -8

This corresponds to option A.

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